Physics, 23.04.2020 01:27, MysteryDove12

A motorcycle daredevil plans to ride up a 2.0-m-high, 20° ramp, sail across a 10-m-wide pool filled with hungry crocodiles, and land at ground level on the other side. He has done this stunt many times and approaches it with confidence. Unfortunately, the motor-cycle engine dies just as he starts up the ramp. He is going 11 m/s at that instant, and the rolling friction of his rubber tires (coefficient 0.02) is not negligible. Does he survive, or does he become croco-dile food? Justify your answer by calculating the distance he travels through the air after leaving the end of the ramp

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answered: josebienka

He becomes a croco-dile food

Explanation:

From the question we are told that

The height is h = 2.0 m

The angle is $\theta = 20^o$

The distance is w = 10m

The speed is u = 11 m/s

The coefficient of static friction is $\mu = 0.02$

At equilibrium the forces acting on the motorcycle are mathematically represented as

$ma = mgsin \theta + F_f$

where F_f is the frictional force mathematically represented as

$F_f =\mu F_x =\mu mgcos \theta$

where F_x is the horizontal component of the force

substituting into the equation

$ma = mgsin \theta + \mu mg cos \theta$

$ma =mg (sin \theta + \mu cos \theta )$

making a the subject of the formula

$a = g(sin \theta = \mu cos \theta )$

substituting values

a = 9.8 (sin(20) + (0.02 ) cos (20 ))

= 3.54 m/s^2

Applying " SOHCAHTOA" rule we mathematically evaluate that length of the ramp as

$sin \theta = \frac{h}{l}$

making the subject

$l = \frac{h}{sin \theta }$

substituting values

$l = \frac{2}{sin (20)}$

l = 5.85m

Apply Newton equation of motion we can mathematically evaluate the final velocity at the end of the ramp as

v^2 =u^2 + 2 (-a)l

The negative a means it is moving against gravity

substituting values

v^2 = (11)^2 - 2(3.54) (5.85)

$v= \sqrt{79.582}$

= 8.92m/s

The initial velocity at the beginning of the pool (end of ramp) is composed of two component which is

Initial velocity along the x-axis which is mathematically evaluated as

v_x = vcos 20^o

substituting values

v_x = 8.92 * cos (20)

= 8.38 m/s

Initial velocity along the y-axis which is mathematically evaluated as

$v_y = vsin\theta$

substituting values

v_y = 8.90 sin (20)

= 3.05 m/s

Now the motion through the pool in the vertical direction can mathematically modeled as

$y = y_o + u_yt + \frac{1}{2} a_y t^2$

where y_o is the initial height,

u_y is the initial velocity in the y-axis

a_y is the initial acceleration in the y axis with a constant value of ( g = 9.8 m/s^2 )

at the y= 0 which is when the height above ground is zero

Substituting values

0 = 2 + (3.05)t - 0.5 (9.8)t^2

The negative sign is because the acceleration is moving against the motion

-(4.9)t^2 + (2.79)t + 2m = 0

Solving using quadratic formula

$\frac{-b \pm \sqrt{b^2 -4ac} }{2a}$

substituting values

$\frac{-3.05 \pm \sqrt{(3.05)^2 - 4(-4.9) * 2} }{2 *( -4.9)}$

$t = \frac{-3.05 + 6.9}{-9.8} \ or t = \frac{-3.05 - 6.9}{-9.8}$

$t = -0.39s \ or \ t = 1.02s$

since in this case time cannot be negative

t = 1.02s

At this time the position the motorcycle along the x-axis is mathematically evaluated as

x = u_x t

x =8.38 *1.02

x =8.54m

So from this value we can see that the motorcycle would not cross the pool as the position is less that the length of the pool

answered: Guest

b) returns freshwater to the earth.

c) returns freshwater to the earth.c) occurs after condensation.

d) returns freshwater to the earth.c) occurs after condensation.d) roughly equal to the amount of evaporation.

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answered: Guest

answer

procedural programming, object-oriented programming

explanation

procedural programming is a type of computer programming language that specifies a series of well structured steps and procedures within its development period of time. it contains a systematic order of statements, functions and commands to complete a computational task or program. it is centered on creating procedures. while object oriented programming is a programming language that is centered on creating objects rather that actions and data rather than logic.. it has four principles which are inheritance, polymorphism, abstraction and encapsulation