Determine the maximum force P P that can be applied without causing the two 43- kg kg crates to move. The coefficient of static friction between each crate and the ground is μ s μs = 0.31.

The maximum force that can be applied without causing the two 43- kg crates to move is 2.7KN

Explanation:

Given data

μ coefficient of friction 0.31

mass of two crates =2*43kg

=86kg

Weight of the two crates =mg

Assuming g= 9.81m/s²

W =86*9.81= 843.66N

We know that force against friction is given by

W =μR

Where

μ is coefficient of static friction

R limiting force

To solve for let's make it the subject of the formula

R= W/μ

R=843.66/0.31

R= 2721.5N

R= 2.7KN

answer; i believe the correct answer is (40,000 j) good luck

it breaks and dirupture other materials and other sencews from the bottom