A 12-kg bowling ball is rolled toward a stationary, 0.9-kg bowling pin at 2.4m/s to the right. After the collision, the bowling ball continues to move in the same direction at 1.3m/s.

Determine the final velocity of the bowling pin.

14.6m/s

Explanation:

elastic collision formula

mv1+mv2=mv1'+mv2'

mv1= mass times velocity of the first object

mv2= mass times velocity of the second object

mv1'=mass times velocity of the first object after the collision

mv2= mass times velocity of the second object after the collision.

we know that the pin is not moving so we multiply 0 or its velocity by the mass 0.9kg this equals zero so we don't add this part to the equation.

mv1=mv1'+mv2'

plugin the values and solve using order of operations

12kg(2.4m/s)=12kg(1.3m/s)+0.9kg(v2')

28.8kg.m/s=15.6kg.m/s+0.9kg(v2')

at this point you need to move 15.6kg.m/s to the other side of the equation so subtract 15.6kg.m/s to 28.8kg.m/s

28.8kg.m/s=15.6kg.m/s+0.9kg(v2')

28.8kg.m/s - 15.6kg.m/s= 0.9kg(v2')

finally Divide by 0.9kg in order to leave v2' in one side.

13.2kg.m/s=0.9kg(v2')

13.2kg.m/s÷0.9kg=v2'

14.6kg.m/s=v2'

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get

convex lenses are thicker at the middle. rays of light that pass through the lens are brought closer together (they converge). a convex lens is a converging lens. when parallel rays of light pass through a convex lens the refracted rays converge at one point called the principal focus.