Amusement Park Ride At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats facing the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of 3.03 m/s, and an 80.7 kg person feels a 576 N force pressing against his back. What is the radius of a chamber?

Explanation:

Amusement Park ride has a circular motion path.

At an instant, the speed of the is

v = 3.03m/s

Mass of a person is

M = 80.7kg

And he felt a force pressing against it back I.e centripetal force

Fc = 576N

Radius of the chamber

Using Circular motion.

Centripetal force is given as

Fc = m•ac

Where m is mass

And ac is centripetal acceleration.

Then, centripetal acceleration is give as

ac = v²/r

So,

Fc = mv²/r

Making r subject of formulas

r = mv² / Fc

Where,

m is mass m = 80.7kg

v is velocity v = 3.03m/s

Fc is centripetal force Fc = 576N

Then,

r = mv² / Fc

r = 80.7 × 3.03² / 576

r = 1.29m

The radius of the chamber is 1.29m

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this