A 1.0 m long piece of coaxial cable has a wire with a radius of 1.1 mm and a concentric conductor with inner radius 1.3 mm. The area between the cable and the conductor is filled with a dielectric. If the voltage drop across the capacitor is 6000 V when the line charge density is 8.8 μC/m, find the value of the dielectric constant. (k = 1/4πε₀ = 8.99 × 109 N · m²/C²)A) 4.8
B) 5.3
C) 4.4
D) 5.7

C) 4.4

Explanation:

The potential of a cylindrical capacitor is given by the formula:

where:

k : Coulomb Constant

L : length of the capacitor

a : outer radius

b : inner radius

V : potential

By replacing we obtain:

Hence, the answer is C) 4.4 (4.35 is approximately 4.4)

hope this helps!!

answer is c

explanation:

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.