Consider 500 g of silver (atomic mass 107 g/mol). Assume that the temperature is high enough that equipartition applies. We heat the silver by immersing it in water; by measuring the temperature change of the water we compute that 300 J of heat energy entered the silver.

What was the change in temperature of the silver?

A. 2.57 K
B. 0.6 K
C. 4.99 K
D. 169 K
E. 0.0466 K

A. 2.57 K

Explanation:

From specific heat capacity,

Q = cmΔT Equation 1

Where Q = Amount of heat that entered into silver, m = mass of silver, c = specific heat capacity of silver, ΔT = change in temperature of the silver.

make ΔT the subject of the equation

ΔT = Q/cm Equation 2

Given: Q = 300 J, m = 500 g = 0.5 kg

Constant: c = 233 J/kg.K

Substitute into equation 2

ΔT = 300/(0.5×233)

ΔT  = 300/116.5

ΔT = 2.57 K

Hence the right option is A. 2.57 K

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

c) up

hope this