A 2.40 kg stone is sliding in the +r-direction on a horizontal,
frictionless surface. It colli...
Physics, 19.04.2020 21:48, snikergrace
A 2.40 kg stone is sliding in the +r-direction on a horizontal,
frictionless surface. It collides with a 4.00 kg stone at rest. After the col-
lision the 2.40 kg stone is moving at 3.60 m/s at an angle of 30.0" mea-
sured from the +x-direction toward the +y-direction, and the 4.00 kg
stone is moving at an angle of 45.0 measured from the +x-direction
toward the-y-direction. (a) What is the y-component of momentum of
the 2.40 kg stone after the collision? What must be the y-component
of momentum of the 4.00 kg stone after the collision? (b) What is the
speed of the 4.00 kg stone after the collision? (c) What is the x-component
of the total momentum of the two stones after the collision? (d) What is
the speed of the 2.40 kg stone before the collision?
Answers: 3
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