A loudspeaker diaphragm is producing a sound for 4.6 s by moving back and forth in simple harmonic motion. The angular frequency of the motion is 2.57 x 104 rad/s. How many times does the diaphragm move back and forth

Number of times the  diaphragm move back and forth is  5.59×10^4

Explanation:

Given data,

ω=4.6 s

we have the formula

f=ω/2π

The number of times the diaphragm moves back and forth in 4.6 s is

Number of times= ft

Number of times= ft

                           =(ω/2π) t

                          =(7.54×10^4 rad/sec)(4.6 s)/2π

Number of time=5.59×10^4

Number of times the  diaphragm move back and forth is  5.59×10^4

i dont know but

explanation:

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