You leave the doctor's office after your annual checkup and recall that you weighed 688 N in her office. You then get into an elevator that, conveniently, has a scale. Find the magnitude and direction of the elevator's acceleration if the scale readsQ: Find the magnitude of the elevator's acceleration if the scale reads 726 NQ: Find the direction of the elevator's acceleration if the scale reads 726 NQ: Find the magnitude of the elevator's acceleration if the scale reads 598 NQ: Find the direction of the elevator's acceleration if the scale reads 598 N

Explanation:

weight of the person = 688 N

a) reading while in the elevator using the scale was  726 N

since when the elevator is going upward the floor of the elevator and the the scale pushes against the person leading to the person experiences a normal force greater than the weight as a result of the acceleration of the elevator and also

F = ma  and W, weight = mg

mass of the body = weight / g = 688 / 9.8 = 70.20 kg

net force on the body = force of normal - weight of the body = 726 - 688 = 38 N

ma = 38 N

70.20 kg × a ( acceleration) = 38 N

a = 38 / 70.20 = 0.54 m/s² and the elevator is moving upward

b) net force, ma = force of normal - weight of the body = 598 - 688 = -90 N

a = -90 / 70.20 = -1.282 m/s² and the elevator is coming downward

answer: option c. i.e. electric current flowing “downhill” from the negative electrode to the positive electrode in a battery

explanation:

the water analogy to the circuits define the pipes (water flows) to the electric current. now, we know that the electric current flows from the positive terminal to the circuit (as shown in the diagram attached).

hence, option c is the correct answer.