A point charge q1=8.60 nC is fixed at the origin. A second point charge q2=5.30 nC is fixed at the point x=10.0 cm. (a) Find the electric potential at point A, located at xA=14.0 cm. (b) Find the total electric field (magnitude and direction) at point B, located at xB=6.00 cm.

(a) 1745.36 V

(b) 8312.5 N/C

Explanation:

q1 = 8.6 nC at origin

q2 = 5.3 nC at x = 10 cm

(a)

Let the electric potential at A is V.

The formula for the electric potential is given by

The electric potential at A due to charge q1 is

V1 = 552.86 V

the electric potential at A due to charge q2 is

V2 = 1192.5 V

The total potential at A is

V = V1 + V2 = 552.86 + 1192.5 = 1745.36 V

(b)

The formula for the electric field is given by

The electric field due to charge q1 at B is

  towards right

E1 = 21500 N/C towards right

The electric filed due to charge q2 at B is

  towards left

E2 = 29812.5 N/C towards left

ne electric filed at B is

E = E2 - E1

E = 29812.5 - 21500 = 8312.5 N/C towards origin

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.

it's when something is going so fast it makes a loud noise, breaking the sound barrier, for example: a jet makes a loud noise, not only cause of the jet but because they reached a point where they went so fast that you can year the noise from various parts, kinda like a police car, lets say the car was going   so fast that you hear the siren of the cop car right next to you, but the car is probably a mile a way, it's cos the siren was next to you a few seconds if you understand me