The emf of a battery is 12 volts. When the battery delivers a steady current of 0.5 ampere to a load, the potential difference between the terminals of the battery is 10 volts. What terminal voltage would you expect if the battery were connected to a load with less resistance?

The terminal voltage would increase to be > 10 V

Explanation:

Battery emf = 12 volt

Potential difference at 0.5 ampere load in between the terminals is 10 volts

The formula for terminal voltage is

V = emf - IR

Where:

I = Current = 0.5 A

R = Resistance

Therefore, when V = 10 volt, we have

10 V = 12 V - 0.5 × R₁

∴ R₁ = 4 Ω

When the resistance of the load is lower say R₂ < R₁, then we have

V₂ = 12 V - 0.5 × R₁ = 12 V - 0.5 × R₂ < R₁

= 12 V -<0.5 × R₁

Since V₁ = 12 V - 0.5 × R₁

V₂ > V₁ and the terminal voltage would increase.

V₂ > 10 V.

nec chapter 5 contains

c. information on special occupancy areas

nec chapter 6 covers

a. special equipment

which of the following rules contain the words shall or shall not and must be adhered to?

b. mandatory rules

which of the following rules identify actions that are allowed but not required and typically cover options or alternative methods?

c. optional rules

which of the following serves as the introduction to the nec and provides an overview of the book?

a. nec article 90

organizations that test products for safety are

c. nrtls

the nec is published by the

a national fire protection association

the nec is divided into

b. 9 chapters

the nec provides informative annexes for

c. informational materials and examples

two terms from nec article 100 that trainees should become familiar with are

b. labeled and listed

explanation: