Near the surface of Venus, its atmosphere has a pressure fv= 91 times the pressure of Earth's atmosphere, and a particle density of around rhov = 1.05 × 1027 m-3. What is the temperature of Venus' atmosphere (in C) near the surface? g

Explanation:

We shall use gas law equation and modify it to include number density of particle as follows

PV = n RT , n is no of moles

P = (n / V)  RT

At earth , P = a atm , n = 6.02 x 10²⁶/22.4  , V = 1 m³ , R is constant , T = 273

(1 mole of a gas occupies  22.4 litre volume and contains 6.02 x 10²³ no of gas molecules .  1 liter = 10⁻³ m³ . )

1 = 6.02 x 10²⁶ x R x 273 / 22.4

At Venus P = 91 atom , n = 1.05 x 10²⁷ , V = 1 m³ , R is constant , T = ?

91 =  1.05 x 10²⁷ R x T

dividing the two equations

91 / 22.4  =  1.05 x 10²⁷ R x T / 6.02 x 10²⁶ x R x 273

91 x 6.02 x 273/ 22.4   = 1.05 x 10 T

T = 91 x 6.02 x 273 / (10.5 x 22.4 )

= 635.86  K

= 362.86 degree Celsius.

the answer is d

lies a supermassive black hole called sagittarius a*, or sgr a* for short.

with 5 seconds, no, but over time if the police car stays at 65m/s ad the speeding car stays at 60, then obviously yes, but the answer to your question would be, no.

hope this : )