Katya is training for an upcoming gymnastics competition and needs to improve her upper body strength. At the moment, she can only support at most 180% of her body weight when she’s hanging off of equipment. Misha, a close friend and circus performer, suggests that she train on a swinging trapeze. Katya grabs onto the trapeze which hangs off a pair of cables of length ` that initially make an angle of 60.0◦ with the vertical. She steps off the platform and swings forward. To what height will she fall/rise as she swings? Will Katya swing back to the platform?

she will fall to an height of 21.09° only, beyond such an height ; the spring will break.

Katya will not be able to swing to the platform because the angle will be between -21.09° and 21.09° from vertical

Explanation:

If the distance is from the point of angle A to angle B , partitioned by a perpendicular line in the middle then, The conservation of energy between A and B can be expressed as :

where ; the height h =

T = mg(3 cos θ - 1)

Given that:

T = 180 % = 1.8 mg

Then:

1.8 mg = mg(3 cos θ - 1)

2.8 mg = (3 cos θ - 1)

cos θ =

θ = cos ⁻¹ (0.933)

θ = 21.09°

Therefore, she will fall to an height of 21.09° only, beyond such an height ; the spring will break.

Katya will not be able to swing to the platform because the angle will be between -21.09° and 21.09° from vertical

colorectal cancer may also develop from areas of abnormal cells in the lining of the colon or rectum. this area of abnormal cells is called dysplasia and is more commonly seen in people with certain inflammatory diseases of the bowel such as crohn's disease or ulcerative colitis.