A 3.13 kg particle has a velocity v3.13 kg = a ˆi + b ˆj, where a = 24.2 m/s and b = 1.35 m/s, and a 2.81 kg particle has a velocity v2.81 kg = c ˆi + d ˆj, where c = 1.27 m/s and d = 8.54 m/s. Find the speed of the center of mass. Answer in units of m/s.

The speed of the center of mass  is

Explanation:

The speed of center of mass:

When a system of particles is moving, then the center of mass moves along with the system.

The center of mass velocity is ratio of the sum of momentum ( mass times velocity) to total mass of the system.

Given that,

A 3.13 kg particle has a velocity , where a= 24.2 m/s and b=1.35 m/s

and other particle has a velocity , where c= 1.27 m/s and d=8.54 m/s

Here,  , = 3.13 kg

, = 2.81 kg

The speed of the center of mass  is

      m/s

think its the third option

false br