Archerfish are tropical fish that hunt by shooting drops of water from their mouths at insects above the water's surface to knock them into the water, where the fish can eat them. A 65 gg fish at rest just at the surface of the water can expel a 0.30 gg drop of water in a short burst of 5.0 msms. High-speed measurements show that the water has a speed of 2.5 m/sm/s just after the archerfish expels it.
A) What is the speed of the archerfish immediately after it expels the drop of water?

Speed = 0.012 m/s

Explanation:

We are given;

Mass of fish = 65g = 65 x 10^(-3)kg

Mass of water it can expel = 0.3g = 0.3 x 10^(-3)kg

Speed of water = 2.5 m/s

Since there is no external force given in fish drop system, linear momentum is conserved. From conservation of linear momentum;

m1v1 = m2v2

So,

65 x 10^(-3) x V1 = 0.3 x 10^(-3) x 2.5

V1 = 0.3 x 2.5/65 = 0.012 m/s

answer; /// i believe that the correct answer is (c)

it is very well related to a lot of things but with my limited knowledge i can confidently say that the answer is space.