. An express train passes through a station. It enters with an initial velocity of 22.0 m/s and decelerates at a rate of 0.150 m/s2 as it goes through. The station is 210 m long. (a) How long is the nose of the train in the station

Explanation:

Give it that,

Initial velocity

u = 22m/s

Deceleration a = - 0.15m/s2

Time taken to travel a station long of 210m

Using equation of motion

Let know the final velocity, when it leaves the station

v² = u²+2as

v² = 22²+2×(-0.15)×210

v² = 484—63

v² = 421

v =√421

v = 20.52m/s

Then,

Using equation of motion to find time taken

v = u + at

20.52 = 22 +(-0.15)t

20.52-22 = -0.15t

-0.15t = -1.48

t = -1.48/-0.15

t = 9.88 sec

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.