A beam of protons is moving in the x direction with a speed of 10.6 km/s through a region in which the electric field is perpendicular to the magnetic field. The beam is not deflected in this region. If the magnetic field has a magnitude of 0.802 T and points in the y direction, find the magnitude and direction of the electric field. Give the x, y, and z component of the electric field.

E= 8501.2

Explanation:

Given Data;

Speed = 10.6 km/s = 10.6*10^3 m/s

Magnitude = 0.802 T

The magnitude of the electric field is calculated using the formula;

q E = q v B

E = v B

   = 10.6 *10^3 * 0.802

   = 8501.2

The direction of the electric field will point along the negative z-axis

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .