A small spotlight mounted in the bottom of a swimming pool that is 4.3 m deep emits light in all directions. On the surface of the pool, directly above the light, the area illuminated is a circle. Determine the maximum radius of this circle. The index of refraction of water is 1.33.

Radius = 4.9m

Explanation:

The critical angle in optics refers to the angle of incidence, beyond which the total internal reflection of light occurs.

The formula for critical angle is;

θ_crit = sin^(-1)(n_r/n_i)

Where:

θ_crit = The critical angle.

n_r = refraction index.

n_i = incident index.

In this case n_i is refraction index of water which is given 1.33

While n_r is the refraction index of air which has a value of 1.

Thus,

θ_crit = sin^(-1)(1/1.33)

θ_crit = 48.75°

In critical angle statements, If the incident ray is precisely at the critical angle, the refracted ray becomes tangent to the boundary at the incidence point and propagates along the interface surface and there is no reflected ray. Thus;

Radius(r) = d.tan θ_crit

Radius = 4.3tan 48.75

Radius = 4.9m

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

h o h o hope you have a merry christmas!

this would be about 43%