A metal microelectrode has a tip that can be modeled as being cylindrical. The metal itself is 1X10^-6m in diameter, adn the tip region is 3mm long. The metal insulation material 0.2 x10^-6 m thick. The insulation material has a relative dielectric constant of 1.67. Only the base of the cylinder is free of insulation. What is the resistance associated with the tip of this microelectrode

Resistance   =1.27*10¹¹

Explanation:

Given Data:

Diameter (d) = 1X10^-6m

Length (L) = 3mm = 0.003m

Thickness = 0.2 x10^-6 m

Dielectric constant = 1.67

Resistivity = 10^3 Ohms/cm²

Calculating the cross sectional area, we have

A = πd²/4

   = π*(1*10⁻⁶)²/4

    =3.142*10⁻¹²/4

     = 7.855 *10⁻¹³ m²  = 7.855 *10⁻⁹cm²

Calculating resistance using the formula;

R = Rs/A

  = 1000/7.855 *10⁻⁹

  =1.27*10¹¹

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

there are no atoms