Suppose 1 kg each of water (4.19 J/(g ⋅∘C)), brick (0.90 J/(g⋅∘C)), iron (0.46 J/(g⋅∘C)), and olive oil (1.79 J/(g⋅∘C)) were held at the same initial temperature and heated for an equivalent amount of time. Indicate their relative final temperatures from lowest (left) to highest (right). Assume no heat is lost to the surroundings. You can use the Intro tab of the PhET to help visualize the temperature changes. (Assume that the mas of the water, iron, and olive oil is 1 kg each and that the mass of the brick is 0.5 kg.)

Explanation:

For rise in temperature due to addition of heat, the formula is as follows

Q = m s Δ t , Q is amount of heat added , m is mass , s is specific heat and

Δ t  is rise in temperature .

Δ t = Q / ms

For water , iron , olive oil mass is 1 kg

So

for water,

Δ t = Q / 4.19

for iron,

Δ t = Q / .46

for olive oil,

Δ t = Q / 1.79

For brick

Δ t = Q / .5 x .9

= Q / .45

Lower the denominator , higher the value.

So

Q / 4.19 < Q / 1.79 <Q / .46 <Q / .45

Tfinal (water)<Tfinal (olive oil)Tfinal (iron)Tfinal (brick )

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s

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