Suponiendo que se mide la longitud de una cuadra de 100 m de longitud con un error de 40 cm; luego se mide la altura de un poste de señalización de 2 m con un error de 4 mm ¿en cuál de las medidas se obtiene mayor exactitud? Determinar el error relativo y el error porcentual

The pole measure has greater accuracy

Explanation:

For the case of the block measure:

absolute error: 40 cm = 0.4 m

actual measure: 100 m

Relative error = absolute error/actual measure =  0.4/100 = 0.004

percentage error = Relative error * 100 = 0.004*100 = 0.4 %

For the case of the pole measure:

absolute error: 4 mm = 0.004 m

actual measure: 2 m

Relative error = absolute error/actual measure =  0.004/2 = 0.002

percentage error = Relative error * 100 = 0.002*100 = 0.2 %

Greater accuracy correspond to the lower error

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

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