You just calibrated a constant volume gas thermometer. The pressure of the gas inside the thermometer is 240.0 kPa when the thermometer is in contact with boiling water. The boiling water is under regular atmospheric pressure. What is the temperature of the thermometer, when it reads a pressure of 431.0 kPa?

396.97°C

Explanation:

Charles' Law explains that at constant volume, the pressure of an ideal gas is directly proportional to its temperature (in Kelvin).

P₁ ∝ T₁

P₁ = kT₁

k = constant of proportionality

(P₁/T₁) = (P₂/T₂)

P₁ = 240.0 kPa

T₁ = Boiling point of water = 100°C = 373.15 K

P₂ = 431.0 kPa

T₂ = ?

(240/373.15) = (431/T₂)

T₂ = (431 × 373.15) ÷ 240

T₂ = 670.12 K

T₂ = 396.97°C

Hope this Helps!!!

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

wind moving at higher speeds will transfer more energy to the water, resulting in stronger waves.