A plane parallel plate capacitor has plates of 10 cm2 area that are 1.0 mm apart. At an instant when charge is being accumulated on the plates at a rate of 12 nC/s, the displacement current between the plates is

Explanation:

We are given:

•Area of plates, a = 10cm²

Convert to meters we have

•Distance btw plates, d= 1.0mm convert to meters, we have

•Rate of charge, q=12nC/s

The magnetic field between the plates and the magnetic field outside the plates of a capacitor are the same, and also the conduction and displacement current are the same.

The current of a capacitor is given by charge per unit time

Thus we have, i =12nC/s

C/s = A

lexy is right because she has the labeled s

6 cos 34, 6 sin 34 trig