Arugby player passes the ball 7.00 m across the field, where it is caught at the same height as it left his hand. if the pass was thrown with a 14.2 degree angle, with an initial speed was 12.0 m/s, assuming that the smaller of the two possible angles was used, how long did this pass take in seconds?

This projectile has been thrown in an oblique movement, so it’s moving in x and in y at the same time. Vy varies due to gravity, and Vx is a constant as there is no gravity in the horizontal direction. In order to calculate Vx, you have to use the angle: Vx=V*cosa=12m/s*cos(14.2)= 11.6m/s So now you should use Vx the same way it is used in a uniform linear movement. d=v*t dx=vx*t t=dx/vx=7m/(11.6m/s)=0.603s