Abare helium nucleus has two positive charges and a mass of 6.64 ✕ 10-27 kg. (a) calculate its kinetic energy in joules at 4.60% of the speed of light. j. (b) what is this in electron volts? ev. (c) what voltage would be needed to obtain this energy? v

The relativistic mass is almost identical to the rest mass.
If the rest mass is exactly 6.64000 x 10⁻²⁷ kg, then the relativistic
mass, rounded to the third significant figure, is  6.65 x 10⁻²⁷ kg.

a).  Kinetic energy = (1/2) (mass) (speed)²

Speed = (0.046) x (299,792,458 m/s)

         KE = (1/2) (6.65 x 10⁻²⁷) (1.902 x 10¹⁴)  =  6.32 x 10⁻¹³ joule

b).  (6.32 x 10⁻¹³ joule) x (6.242 x 10¹⁸ eV/joule)  =  3.947 x 10⁶  eV

c).  1 elementary charge = 1.60 x 10⁻¹⁹ Coulomb

      Charge of 1 Helium nucleus = 2 elementary charges = 3.20 x 10⁻¹⁹ C.

 6.32 x 10⁻¹³ joule / 3.20 x 10⁻¹⁹ C  =  1,975,000 joule/Coulomb

                                                          =   1,975 kV .

That's an awful lotta volts for a straight accelerator.
I see two possibilities:

a).  I made a mistake in my orders of magnitude.  If so, I leave it
to you to find my mistake.  I feel that I've already contributed enough
to earn 5 points. 

b).  If the math is true, then in order to accelerate alpha particles to
3.95 MeV, you'll need some sort of a pulsed scheme, as in a cyclotron,
synchrotron, or the LHC if you can buy some time.

You're not too generous with your points, are you Pap3, or whatever
your name is today, bless your shiny roboticles.

The answer should be a.