What is the current in the 60.0 Ω resistor?
A. 1.50 A
B. 80.0A
C. 12.0A
D. 2.00A

1.50 A

Explanation:

Since the resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.

i.e Rtotal = R1 + R2

R1 = 60Ω

R2 = 20Ω

Rtotal = 60Ω + 20Ω = 80Ω

Given that,

voltage of circuit (V) = 120.0 V

resistance of circuit (R) = 80Ω

current of circuit (I) = ?

Since, voltage, resistance and current are involved, apply the formula for ohms law to get current

Voltage = current x resistance

120.0V = I x 80Ω

I = 120.0V / 80Ω

I = 1.50 Amps

Since, the 60Ω and 20Ω resistors are connected in series, the same current of 1.50 Amps flows through both.

Thus, the current in the 60Ω is 1.50 Amps

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.