If the work required to stretch a spring 4 feet beyond its natural length is 18 foot-pounds, how much work is needed to stretch it 20 inches beyond its natural length? Your answer must include the correct units. (You may enter lbf or lb*ft for ft-lb.)

Explanation:

work done by stretching a spring by x m

= potential energy of stretched spring = 1/2 k x² where k is spring constant and x is extension .

18 = 1/2 k x 4² ( Given )

k = 2.25 poundal / ft

work needed to stretch 20 inch or 20/12 ft

= 1/2 x k (20/12)²

= 1/2 x 2.25 x 400/144

= 3.125 ft-poundal.

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is