Wire carrying a current of 1.85 A is bent into the shape of a square loop of side length 9.26 cm and is placed in the xy-plane. What is the torque on the wire loop if there is a uniform magnetic field of 0.259 T pointing in the +z direction

0.0041 Nm

Explanation:

Parameters given:

Current, I = 1.85 A

Length of side of the square, L = 9.26 cm = 0.0926 m

Magnetic field, B = 0.259 T

The magnetic torque on the loop is given as:

τ = N * I * A * B

Where N = number of turns = 1

I = current

A = area of the loop = L * L = 0.0926²

B = magnetic field

We're told that current is acting on a perpendicular axis to the magnetic field.

Therefore:

τ = 1 * 1.85 * 0.0926² * 0.259

τ = 0.0041 Nm

The magnetic torque is 0.0041 Nm.

f=ma newton's second law 7x8=56n