A capacitor consists of two parallel plates, each with an area of 17.0 cm2 , separated by a distance of 0.150 cm . The material that fills the volume between the plates has a dielectric constant of 5.00. The plates of the capacitor are connected to a 400 V battery.

What is the capacitance of the capacitor?

What is the charge on either plate?

How much energy is stored in the charged capacitor?

Explanation:

Area of plate

A = 17cm² = 0.00017m²

Separation distance

d = 0.15cm = 0.0015m

Dielectric material k = 5

The plate of the capacitor are connected to

Voltage =400V

a. Capacitance of the capacitor?

Capacitance of the capacitor can be determine by

C = kεA/d

ε = 8.854 × 10^-12F/m

C=5×8.854×10^-12×0.00017/0.0015

C = 5.017 × 10^-12 F

C = 5.017 pF.

The capacitance of the capacitor is 5.017 picoFarad

b. The charge on a capacitor is given as

q = CV

q = 5.017 ×10^-12 × 400

q = 2.007 × 10^-9

q = 2.007 nC

Each plate has a charge of 2.007nC but one is positive and the other is negative

Q1 = +2.007nC

Q2 = - 2.007nC

So the charge on each plate is ±2.007 nano Coulombs

c. Energy stored in a capacitor is given as

E = ½CV²

E = ½ × 5.017×10^-12 × 400²

E = 4.0136 ×10^-7 J

So the energy stored by the capacitor is 4.0136 × 10^-7 J.

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles