A uniform magnetic field passes through a horizontal circular wire loop at an angle 17.3 ° 17.3° from the normal to the plane of the loop. The magnitude of the magnetic field is 2.55 T 2.55 T , and the radius of the wire loop is 0.250 m 0.250 m . Find the magnetic flux Φ Φ through the loop.

4.78 × 10⁻³ T.m²

Explanation:

The expression for the magnetic flux is given by

∅ = BAcosФ

where B = magnetic field strength

A = Area of circular loop = πr²

r = radius of the wire loop

substitute πr² for A in the first equation

∅ = Bπr²cosФ

∅ = 2.55 × 3.14 × 0.025² × cos 17.3°

∅ = 4.78 × 10⁻³ T.m²

OR

0.00478 T.m²

the independent variable, or the one that is intentionally manipulated is the speed.