A loop of wire carries a conventional current of 0.9 amperes. The radius of the loop is 0.05 m. Calculate the magnitude of the magnetic field at a distance of 0.46 m along the axis of the loop, from the center of the loop. B

0.098 T

Explanation:

Parameters given:

Current in the wire, I = 0.9 A

Radius of loop, r = 0.05 m

Distance of the point of consideration, L = 0.46 m

The magnetic field, B, at distance, L, due to a current, I, flowing in a wire of radius, r, is given as:

B = (N*r*I) / L

Where N = number of turns in the loop = 1

Therefore, B is:

B = (1 * 0.05 * 0.9) / 0.46

B = 0.098 T

The magnetic field, B is 0.098 T

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.