Physics, 08.04.2020 00:03, kharmaculpepper
One hundred jumping beans are placed along the center line of a gymnasium floor at intervals of six inches (in.). Twelve hours later, the distance of each jumping bean from the line is measured. The sum of the squares of the distances divided by 100 is 36in.2 . Note that no constraint is given on the direction or angle of the jump.(a) Calculate the diffusion coefficient of the jumping beans.
(b) If the mean jump (or roll) distance of a bean is equal to 0.1in., estimate the mean
jump (or roll) frequency of a bean.
Answers: 1
Physics, 21.06.2019 19:30, Jazminfun70
Density of salty water as compared to the density of pure water is(a) is less(b) is always equal(c) is always more(d) may be less or more
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Physics, 22.06.2019 15:00, ttorres013
Consider a uniformly charged ring in the xy plane, centered at the origin. the ring has radius a and positive charge qdistributed evenly along its circumference. a)what is the direction of the electric field at any point on the z axis? . b)what is the magnitude of the electric field along the positive z axis? use k in your answer, where k=14πϵ0. d)the ball will oscillate along the z axis between z=d and z=−d in simple harmonic motion. what will be the angular frequency ω of these oscillations? use the approximation d≪a to simplify your calculation; that is, assume that d2+a2≈a2. express your answer in terms of given charges, dimensions, and constants
Answers: 2
Physics, 22.06.2019 15:50, ksiandua07
An object with initial temperature 130 ∘ f is submerged in large tank of water whose temperature is 50 ∘ f . find a formula for f ( t ) , the temperature of the object after t minutes, if the cooling constant is k = − 0.2 . remember newton's law of cooling (the rate of change of temperature with respect to time is equal to k times the difference between the temperature of the object and the surrounding temperature) ! : )
Answers: 1
One hundred jumping beans are placed along the center line of a gymnasium floor at intervals of six...
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