Billiard ball A, mass 0.17 kg, moving due east with a velocity of 4.0 m/s, strikes stationary billiard ball B, also mass of 0.17 kg. After the collision, ball A moves off at an angle of 30° north of east with a velocity of 3.5 m/s, and ball B moves off at an angle of 60 ° south of east . What is the speed of ball B?

speed of ball B is 0.5 m/s

Explanation:

First the angle at which it's invliy does not matter.

Initial momentum is equall to final momentum.

M1v1 + m2v1 = m1v2 + m2v2

0.17*4 + ( 0.17*0) = 0.17*3.5 + 0.17v2

0.68 + 0= 0.595 + 0.17v2

0.68-0.595= 0.17v2

0.085 = 0.17v2

0.5 = v2

V2 = 0.5 m/s

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.