In a very busy off-campus eatery one chef sends a 235-g broccoli-tomato-pickle-onion-mushro om pizza sliding down the counter from left to right at 1.65 m/s. Almost simultaneously, the other chef launches a 351-g veggieburger-on-a-bun (with everything, but hold the horseradish) along the same counter from right to left at 2.47 m/s. The two delicacies collide head on at the given speeds–the counter is practically friction-free due to accumulated grease–and merge into a single, unbelievably savory serving.

In what direction does the delectible dish move, if it moves at all?

a. to the left

b. to the right

c. doesn't move

At what speed does it move? Enter a positive number.

Ans

mass of broccoli-tomato-pickle-onion-mushroom pizza  m₁ = .235 kg

velocity of broccoli-tomato-pickle-onion-mushroom pizza  v₁ = 1.65 m /s

Its momentum = m₁v₁

= .38775 kg . m/s

mass of veggieburger-on-a-bun m₂ = .351 kg

velocity of veggieburger-on-a-bun v₂ = 2.47 m /s

Its momentum = m₂v₂

= .86697 kg m /s

They are coming from opposing sides so  their net momentum

.86697 -  .38775 = .47922 kg m /s in the direction of veggieburger-on-a-bun

because it had larger momentum.

Applying law of conservation of momentum

total momentum in the beginning = final momentum

.47922 = (m₁ + m₂) v    ;  v is common velocity

v = .47922  / ( .235 + .351 )

= .8178 m / s

81.78 cm /s towards left.

the temperature in kelvin of 2.0 dm3 of an ideal gas is doubled and its pressure is increased by a factor of four. what is the final volume of the gas

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft