A 12.4-g marble is dropped from rest onto the floor 1.56 m below. If the marble bounces straight upward to a height of 0.614 m, what is the magnitude of the impulse delivered to the marble by the floor

The impulse is    

Explanation:

Generally Impulse which the change in momentum  is mathematically represented as

Where m is the mass  with a value 12.4g =

            is the change in velocity which is mathematically represented as

Where s the velocity of the marble drooping and is the velocity of the marble bouncing back

setting up in a coordinate y-axis would show that is moving in the negative y-direction so the  value would be and   is moving in the positive  y-direction so the  value would be

So the formula for would be

General v i mathematically represented as

 Substituting this into the formula for

Now substituting values as given in the question

The impulse is

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.