A 12.4-g marble is dropped from rest onto the floor 1.56 m below. If the marble bounces straight upward to a height of 0.614 m, what is the magnitude of the impulse delivered to the marble by the floor

The impulse is    

Explanation:

Generally Impulse which the change in momentum  is mathematically represented as

Where m is the mass  with a value 12.4g =

            is the change in velocity which is mathematically represented as

Where s the velocity of the marble drooping and is the velocity of the marble bouncing back

setting up in a coordinate y-axis would show that is moving in the negative y-direction so the  value would be and   is moving in the positive  y-direction so the  value would be

So the formula for would be

General v i mathematically represented as

 Substituting this into the formula for

Now substituting values as given in the question

The impulse is

see earlier