A 2.5kg object oscillates at the end of a vertically hanging light spring once every 0.65s .
Part A
Write down the equation giving its position y (+ upward) as a function of time t. Assume the object started by being compressed 17cm from the equilibrium position (where y = 0), and released.
Write down the equation giving its position ( upward) as a function of time . Assume the object started by being compressed 17 from the equilibrium position (where = 0), and released.
y(t)=(0.17m)?cos(2?t0.65s)
y(t)=(0.17m)?sin(2?t0.65s)
y(t)=(0.17m)?cos(0.65s?t)
y(t)=(0.17m)?cos(t0.65s)
Part B
How long will it take to get to the equilibrium position for the first time?
Express your answer to two significant figures and include the appropriate units.
Part C
What will be its maximum speed?
Express your answer to two significant figures and include the appropriate units.
Part D
What will be the object's maximum acceleration?
Express your answer to two significant figures and include the appropriate units.
Part E
Where will the object's maximum acceleration first be attained?
Where will the object's maximum acceleration first be attained?
a. release point
b, equilibrium point
Answers: 2
Physics, 22.06.2019 16:40, Crxymia
Aparticle's position is given by x = 3.00 - 9.00t + 3t2, in which x is in meters and t is in seconds. (a) what is its velocity at t = 1 s? (b) is it moving in the positive or negative direction of x just then? (c) what is its speed just then? (d) is the speed increasing or decreasing just then? (try answering the next two questions without further calculation.) (e) is there ever an instant when the velocity is zero? if so, give the time t; if not, answer "0". (f) is there a time after t = 3 s when the particle is moving in the negative direction of x? if so, give the time t; if not, answer "0".
Answers: 3
A 2.5kg object oscillates at the end of a vertically hanging light spring once every 0.65s .
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