Assume that an average city uses about 8.5×1013J of energy in a day.
A fission-based nuclear bomb (such as those used in World War II) uses the same nuclear reactions and an amount of fuel similar to what you calculated in Part A. We will assume for our approximate calculation that matter to energy conversion is at 0.01%, as in Part A. However, by allowing an uncontrolled chain reaction to occur, all of the bomb's energy can be released in about 1.0×10−6s.
What is the average power Pavg of such a nuclear bomb?
Express your answer in watts to two significant figures.

Pavg = (8.5 × 10²³ W)

Explanation:

The city uses (8.5×10¹³)J of energy in a day,

And this represents only 0.01% of the total nuclear energy released.

All of the energy released in the nuclear fission is (1.0×10⁻⁶) s.

Let the total energy produced be x

0.01% of x = 8.5×10¹³ J

x = (8.5×10¹³) ÷ 0.01% = (8.5×10¹⁷) J

Average power produced = (energy produced)/Time

Pavg = (8.5×10¹⁷)/(1.0×10⁻⁶)

Pavg = (8.5 × 10²³ W)

Hope this Helps!!!

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