A circular loop of radius 0.10 m is rotating in a uniform external magnetic field of 0.20 T. Find the magnetic flux through the loop due to the external field when the plane of the loop and the magnetic field vector are parellel.

The magnetic flux through the loop is 0.006284 m².T

Explanation:

Given;

radius of circular loop, r = 0.1 m

magnetic field strength, B = 0.2 T

Magnetic flux through the loop due to the external field is given as;

Φ = BAcosθ

where;

Φ is magnetic flux

B is the magnetic field strength

A is the area of the loop

θ is the angle of inclination of between the plane of the loop and external magnetic field

A = πr² = π(0.1)² = 0.03142 m²

θ = 0, since they are parallel

Φ = BAcosθ

Φ = 0.2 x 0.03142 x cos0

Φ = 0.006284 m².T

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.