Physics, 06.04.2020 23:08, pierceybbpow8o39
Given one mole of diamond vs one mole of graphite,
G S V
1 mol Graphite 0J 5.74 J/K 5.30 cm^3
1 mol Diamond 2900J 2.38 J/K 3.42 cm^3
(Assume S and V are constant over the temperatures and pressures we’re considering, which is a reasonable approximation.)
(a) At room temperature 300 K, at what pressure does diamond become more stable?
(b) At standard pressure 10^5 Pa, at what temperature does diamond become more stable?
Answers: 3
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Africtionless piston-cylinder contains 50 l of saturated liquid r-134a. the piston has a mass and an area resulting in an applied pressure of 500 kpa on the refrigerant. the refrigerant is now heated until its temperature rises to 70∘c. calculate the work (in kj) done during this process.
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Given one mole of diamond vs one mole of graphite,
G S V
1 mol Graphite 0J 5.74 J/K 5....
G S V
1 mol Graphite 0J 5.74 J/K 5....
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