A car is moving at 5.82 m/s when it accelerates 2.35m/s^2 for 3.25s. what is its final velocity?

13.46 m/s

Explanation:

Initial velocity V1 = 5.82 m/s

acceleration A = 2.35m/s^2

Time taken T = 3.25s

Final velocity V2 = ?

Recall that acceleration is the rate of change of velocity per unit time i.e acceleration = (V2 - V1)/T

2.35m/s^2 = (V2 - 5.82 m/s) / 3.25s

cross multiply

2.35m/s^2 x 3.25s = (V2 - 5.82 m/s)

7.6375m/s = V2 - 5.82 m/s

V2 = 7.6375m/s + 5.82m/s

V2 = 13.46 m/s

Thus, the car final velocity is 13.46 m/s

The final velocity is 13.5m/s

Explanation:

a = (v-u)/t

2.35 = (v-5.82) / 3.25

7.6375 = v - 5.82

v = 7.6375 + 5.82

v = 13.5 m/s