An 870 N firefighter, F_ff, stands on a ladder that is 8.00 m long and has a weight of 355 N, F_ladder. The weight of the ladder acts at its center, and the ladder is leaning against a smooth wall at an angle of 50.0° between the ladder and the ground. The firefighter stands at a point 6.30 m from the base of the ladder. The ground is not smooth and exerts a force, F_ground, on the ladder to keep it from slipping. Determine the forces that the wall puts on the ladder, F_wall, and that the ground puts on the ladder, F_ground.

Ireally just need to get finished with precal! i’m really sorry i have to do this! hope this !

The relationship of both of them

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.