The coefficient of static friction between the bed of a truck and a box resting on it is 0.67. The truck is traveling along a straight horizontal road at 30 m/s. what is the least distance in which the truck can stop if the box is not to slide/

68.46 m.

Explanation:

Given,

coefficient of friction,μ = 0.67

speed of truck, v = 30 m/s

distance travel by the truck to stop = ?

Now,

Calculation of acceleration

we know,

f = m a

and also

f = μ N = μ mg

Equating both the forces equation

m a = μ mg

a = μ g

a = 0.67 x 9.81

a = 6.57 m/s²

Now, using equation of kinematics

v² = u² + 2 a s

0 = 30² - 2 x 6.57 x s

s = 68.46 m

Hence, the minimum distance travel by the truck is equal to 68.46 m.

representative si the final answer! : )

i need the answer to this too but idk it ; -;