Can someone help pls!!

Rp = 10 Ohms; I = 0.9 Amps

Explanation:

Since, there are two resistors each with 20Ω connected in parallel, the total resistance of the combination (Rp) of the circuit is as follows:

i.e 1/Rp = (1/R1 + 1/R2)

1/Rp = (1/20Ω + 1/20Ω)

1/Rp = (1 + 1)/20Ω

1/Rp = 2/20Ω

1/Rp = 1/10Ω

To get the value of Rp, cross multiply

Rp x 1 = 10Ω x 1

Rp = 10Ω

Apply the formula

Voltage V = Current I x Total resistance Rp

I = V/Rp

I = 9V/10Ω

I = 0.9 Amps

Thus, the total resistance is 10 Ohms, the current through the ammeter is 0.9 Amps

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