A charge is accelerated from rest through a potential difference V and then enters a uniform magnetic field oriented perpendicular to its path. The field deflects the particle into a circular arc of radius R. If the accelerating potential is tripled to 3 V, what will be the radius of the circular arc?
Motion of a charged particle in an electric field and in a magnetic field:
When a charged particle moves between two point in an electric field, having a potential difference V, the change in the energy of the particle is given by:
ΔE=qV
Also, when a charged particle moves through a region of magnetic field with its velocity perpendicular to the magnetic field it experiences a force given by:
F=qvB
where:
q is the charge of the particle
v is the speed of the particle
B is the strength of the magnetic field