The universal gas constant is 8.31451 J/K · mol. Calculate the change in internal energy of 7 mol of helium gas when its temperature is increased by 4.9 K. Answer in units of J.

Change in internal energy of the gas is given as

Explanation:

change in internal energy of the ideal gas is given as

here we know that

n = 7 mol

R = 8.31451 J/K-mol

since we know that Helium gas is a monoatomic gas so we have

now we have

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

probably not if net force is zero