A sample of oxygen gas has a volume of 165 mL at a pressure of 0.854 atm. What will the volume of the gas be at a pressure of 2.3 atm if the temperature remains constant?

24.1 mL

Explanation:

Initial volume V1 = 65 mL

Initial pressure P1 = 0.854 atm

Final volume of the gas V2 = ?

Final pressure of the gas P2 = 2.3 atm

Since, pressure and volume are involved while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

0.854 atm x 65 mL = 2.3 atm x V2

55.51 atm mL = 2.3 atm x V2

V2 = (55.51 atm mL / 2.3 atm)

V2 = 24.1 mL

Thus, the final volume of the gas will be

24.1 mL