According to observer O, a blue flash occurs at xb = 10.4 m when tb= 0.124 μs, and a red flash occurs at xr= 23.6 m when tr= 0.138 μs. According to observer O’, who is in motion relative to O at velocity u, the two flashes appear to be simultaneous. Find the velocity u.

u = 95.46 * 10⁶ m/s

Explanation:

For the first observer O,

Time of the blue flash,

Time of the red flash,

Distance covered before the blue flash,

Distance covered before the red flash,  

Difference in time observed by the first observer O,  Δt =

Δt = 0.138 - 0.124 = 0.014  μs

Difference in the distance observed by the observer O, Δx =

Δx = 23.6 m - 10.4 m

Δx = 13.2 m

Since for the observer O', the two flashes are simultaneous, there will be no time difference between the two flashes. i.e. Δt' = 0

Using the lorent'z transformation equation:

...................(1)

But Δt' = 0,

equation (1) becomes

u = 95.46 * 10⁶ m/s

prolly a beacuse the momentuem the car has increases while going down hill

false br