A forklift raises a 1,020 N crate 3.50 m up to a shelf. How much work is done by the forklift on the crate?

The forklift does
J of work on the crate.

Hope this will help u..:)

3570J

Explanation:

Workdone = force x distance

Given

Force = 1020N and

Distance = 3.50m

Workdone = 1020 x 3.50

= 3570J

Work done by the forklift on the crate is 3570J

yup its correct its: c) b b

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray