The hydrogen atom consists of a proton of mass 1.67x10-27 kg and an orbiting electron of mass 9.11x10-31 kg. In one of its orbits, the electron is 5.3x10-11 m from the proton. What is the mutual attractive gravitational force between the electron and the proton?

The mass of the proton,
m
p
=
9.11
×
10
−
31
k
g
The mass of the electron,
m
e
=
1.67
×
10
−
27
k
g
The distance between them,
r
=
5.3
×
10
−
11
m

The gravitational force between two objects of mass,
m
1
, and
m
2
, separated by a distance,
r
, is given by the following equation:

F
=
G
m
1
m
2
r
2

Here,

G
=
6.67
×
10
−
11
m
3
/
k
g
.
s
2
is the gravitational constant.
On plugging the given values, we have:

F
=
6.67
×
10
−
11
×
1.67
×
10
−
27
×
9.11
×
10
−
31
(
5.3
×
10
−
11
)
2
=
3.61
×
10
−
47
N

Wind or electric energy force force of friction