A force of 100 N hangs in the center of a cable between two anchor points that are the same height off the ground and 30 m apart horizontally. The object creates a sag of 2 m in the cable. Find the force exerted by each end of the cable on its anchor point.

378.3N

Explanation:

According to Newton's 3rd law, the force exerting on each anchor points would equal to the tension force T on each cable, which is created to support the 100N in the center

As the system remain balanced, then vertically the tension force would support the 100N

where Θ is the angle between the cable and the vertical line intersecting the force F. As it's 15m halfway between the 2 anchor

therefore 2T0.132 = 100

T = 100/(2*0.132) = 378.3 N

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge